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Find the set of values of x for which `(tan3x-tan2x)/(1+tan3x.tan2x)=1`. |
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Answer» We have, `(tan3x-tan2x)/(1+tan3x.tan2x)=1 rArr tan(3x-2x)=1 rArr tanx=1` `rArr tanx=tanx/4 rArr x=npi+pi/4,n in I` (using `tantheta=tanalpha ltimplies theta= npi+alpha)` But for this value of x, `tan 2x` is not defined. Hence the solution set for `x` is `phi`. |
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