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Find the set of values of x for which the functions f(x) = 3x2 – 1 and g(x) = 3 + x are equal. |
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Answer» f(x) = 3x2 -1; g(x) = 3+x For f(x) = g(x) 3x2 -1 = 3+x 3x2 -x-4 = 0 (3x-4)(x+1) = 0 3x-4 = 0 or x+1 = 0 x = \(\frac{4}{3}\), 1 |
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