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Find the skip distance when the angle of incidence is 200 and virtual height is 50km?(a) 13.22m(b) 13.22km(c) 36.33km(d) 36.33mThe question was posed to me in a job interview.This interesting question is from Virtual Height in division Virtual Height, Critical Frequency and Muf of Antennas |
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Answer» RIGHT answer is (C) 36.33km Easy explanation: Skip distance \(d=2h\sqrt{[\FRAC{f_{MUF}^2}{f_c^2}-1]}=2h\sqrt{[secθ_i^2-1]} =2×50×\sqrt{[(sec20)^2-1]}\) d=36.33km |
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