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find the smallest five digit number which is exactly divisible by 32, 40, and 56. (solution with please) |
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Answer» 1008 0Step-by-step explanation:Start by FINDING the least common multiple of those four NUMBERS. One way to do this is to FACTORISE each of them into PRIME numbers and pick the number which has all of the factors as many times as necessary16 = 2×2×2×218 = 2×3×324 = 2×2×2×330 = 2×3×5So we need four 2×2×2×2 for sixteen, another 3×3 for 18—these will be enough for 24—and a further 5 for 30. So the least common multiple is 2×2×2×2×3×3×5 = 720.Now multiply 720 by the smallest number that results in 10,000 or greater. 720×14 = 10,080.So the answer is 10,080, which is 16×630, 18×560, 24×420, or 30×336. |
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