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Find the smallest no., which when ii) increased by 3 is exactly divisible by the no's 21, 45, 6381 and 210.​

Answer» E have to FIND LCM of 21, 45, 63, 81, 210we will get 5670. To find the NUMBER exactly divisible by 3, we have to subtract 3 from 5670=>5670-3=5667. Therefore answer is 5667.


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