Saved Bookmarks
| 1. |
Find the smallest number when divided by 24 , 36 and 54 gives a remainder of 5 each time first and most explained answer will be marked brainliest |
|
Answer» 221Step-by-step EXPLANATION:Prime factorization of24 = 2 × 2 × 2 × 336 = 2 × 2 × 3 × 354 = 2 × 3 × 3 × 3Required LCM = 2 × 2 × 2 × 3 × 3 × 3 = 216The smallest number which is EXACTLY divisible by 24, 36 and 54 is 216In order to get REMAINDER as 5Required smallest number = 216 + 5 = 221THANKS!I hope it will help you.Good LucK! |
|