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Find the smallest number which leaves remainder 8 and 12 when divided by 28 and 32respectively. class 10 |
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Answer» Answer: GIVEN that the SMALLEST number when divided by 28 and 32 leaves remainder 8 and 12 respectively. 28 - 8 = 20 and 32 - 12 = 20 are divisible by the required numbers. THEREFORE the required number will be 20 LESS than the LCM of 28 and 32. = 224.
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