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find the smallest number which when divided by 1088, 640 and 100 leaves 3 as reminder in each case in |
Answer» STRONG>To Find :-
SOLUTION :- we know that,
so, Prime factors of 1088 , 640 and 100 are :- → 1088 = 2⁶ * 17 → 640 = 2⁷ * 5 → 100 = 2² * 5² LCM = 2⁷ * 5² * 17 = 128 * 25 * 17 = 54400 . therefore, → Required number = 54400 + 3 = 54403 (Ans.) Learn more :- वह छोटी से छोटी संख्या बताईये जिसमे 7,9,11 से भाग देने पर 1,2,3 शेष बचे |
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