1.

Find the smallest number which when increased by 17 is exactly divisible by both 468 and 520.

Answer»

The required number is determine with the help of LCM of 468 and 520.

Using prime factorization, find the LCM:

468 = 22 × 3× 13

520 = 23 × 5 × 13

LCM = 4680

The required number = LCM(468 and 520) – 17

= 4680 – 17 = 4663

The required number is 4663.



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