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Find the smallest perfect square which is divisible by each of the numbers 6 8 12 and 15 |
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Answer» 3600 Step-by-step EXPLANATION: Take LCM of (6,8,12 and 15) = 120 Resolving 120 into prime factors, we get 120 = 2*2*2*3*5 Here 2 is GROUPED in pairs of equal factors. But 2, 3 and 5 are not grouping in pairs of equal factors. Let us multiply 2, 3 and 5 , we get a grouped in pairs of equal factors. 120*2*3*5 = 2*2*2*2*3*3*5*5 3600 = 2*2*2*2*3*3*5*5 Now 3600 is perfect square that is divisible by 6, 8, 12, and 15. |
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