1.

Find the smallest positive integer greater than one which yields a remainder of one when divided by any single positive integer greater than 1. ​

Answer»

Step-by-step explanation:

Since this NUMBER is 1 greater than the number that can be divided by 4, 5, and 6, we have to find the LCM of it. FIRST, let’s find the prime factorizations:

4: 2*2

5: 5

6: 2*3

2*2*3*5 = 60 (Only two 2’s because there is a max of two, LIKE 2*2 is two, and 2 is one, so we take the largest amount, two).

60 + 1 = 61 ANS



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