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Find the speed at which the mass of an electron is double of its rest mass. |
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Answer» Solution :The mass of an elctron at SPEED v is `= m_0 = (sqrt 1 -v ^(2) /C ^(2) )` Where m_0 is its rest mass. If `m= 2 m^(0)` `2 =1/ ( sqrt 1 -v ^(2) /c ^(2) ) ` or, ` 1 - v^(2) / v^(2) = 1 / 4 ` or, v = (sqrt 3) / 2 c = 2.598 XX 10^(8) m s^(-1)` |
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