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Find the square of (i) (a-2b) (ii) (3c + 5 d) |
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Answer» (a-2b)^2= a^2+4b^2-4abdiv by AB on both SIDES,a/b+4b/a=4.2.(3c+5d)^2=9c^2+25d^2+30cd 9c^2+25d^2=-30cd DIVIDE by CD on both sides, 9c/d+25d/c=-30. |
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