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    				| 1. | Find the squares of the numbers given below.(i) 49(ii) 98(iii) 7\(\frac{3}{4}\)(iv) 9.25 | 
| Answer» (i) 492 = (50 – 1)2 = 502 – 2 × 50 × 1 + 1 = 2500 – 100 + 1 = 2401 (ii) 982 = (100 – 2)2 = 1002 – 2 × 100 × 2 + 22 = 10000 – 400 + 4 = 9604 (iii) (7\(\frac{3}{4}\))2 = (8 – \(\frac{1}{4}\))2 = 82 – 2 × 8 × \(\frac{1}{4}\) + (\(\frac{1}{4}\))2 = 64 – 4 + \(\frac{1}{16}\) = 60\(\frac{1}{16}\) (iv) 9.252 = (10 - 75)2 = 102 – 2 × 10 × .75 + (.75)2 = 100 – 15 + 0.5625 = 85. 5625 | |