1.

Find the squares of the numbers given below.(i) 49(ii) 98(iii) 7\(\frac{3}{4}\)(iv) 9.25

Answer»

(i) 492 = (50 – 1)2

= 502 – 2 × 50 × 1 + 1

= 2500 – 100 + 1

= 2401

(ii) 982 = (100 – 2)2

= 1002 – 2 × 100 × 2 + 22

= 10000 – 400 + 4

= 9604

(iii) (7\(\frac{3}{4}\))2 = (8 – \(\frac{1}{4}\))2

= 82 – 2 × 8 × \(\frac{1}{4}\) + (\(\frac{1}{4}\))2

= 64 – 4 + \(\frac{1}{16}\)

= 60\(\frac{1}{16}\)

(iv) 9.252

= (10 - 75)2

= 102 – 2 × 10 × .75 + (.75)2

= 100 – 15 + 0.5625

= 85. 5625



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