Find the standard deviation of the binomial distribution having n = 8

1.	Find the standard deviation of the binomial distribution having n = 8 and probability of failure
Answer» n = 8, q = 23 ∴ p = 1 – q = 1 – \(\frac{2}{3} = \frac{1}{3}\) Standard deviation of the binomial distribution: √npq = \(\sqrt{8\times\frac{1}{3}\times\frac{2}{3}}=\sqrt{\frac{16}{9}}=\frac{4}{3}\) Hence, the standard deviation of the binomial distribution obtained is \(\frac{4}{3}\).

Find the standard deviation of the binomial distribution having n = 8 and probability of failure

Answer»

n = 8, q = 23

∴ p = 1 – q = 1 – \(\frac{2}{3} = \frac{1}{3}\)

Standard deviation of the binomial distribution:

√npq = \(\sqrt{8\times\frac{1}{3}\times\frac{2}{3}}=\sqrt{\frac{16}{9}}=\frac{4}{3}\)

Hence, the standard deviation of the binomial distribution obtained is \(\frac{4}{3}\).