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Find the sum 1^3+2^3+3^3+……………+8^3.(a) 1225(b) 1184(c) 1475(d) 1296I had been asked this question in final exam.My question is from Sum to n Terms of Special Series topic in portion Sequences and Series of Mathematics – Class 11

Answer»

The CORRECT choice is (d) 1296

To EXPLAIN: We know, sum of cubes of first N terms is given by \((\frac{n(n+1)}{2})^2\).

Here, n=8. So, sum = (8*9/2)^2 = 1296.



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