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Find the sum `3/2-5/6+7/(18)-9/(54)+oodot` |
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Answer» Correct Answer - `15/16` `S=3/2-5/6+7/18-9/54+..oo` `rArrS=3(1/2)+5(-1/6)+7(1/18)+9(-1/54)+..` (1) `rArr-1/3S=3(-1/6)+5(1/18)+9(-1/54)+..` (2) Subtracting (2) from (1), we have `4/3S=3(1/2)+[2(-1/6)+2(1/18)+2(-1/54)+…oo]` `=3/2+(2(-1/6))/(1-(-1/3))` `=3/2-(1/3)/(4/3)` `=3/2-1/4` `=5/4` `rArrS=15/16` |
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