1.

Find the sum of all the three digit natural number which are divisible of 7.

Answer»

Heya MATE, Here is UR answer

a(first term) = 105

d =7 (divisiblity by 7)

an= 994

a+(n-1)d=994

105+(n-1)7=994

(n-1) 7=994-105

(n-1) 7=889

n-1=889/7

n-1=127

n=127+1

n=128

Sn=n/2 (a+an)

= \frac{128}{2} (105 + 994)


= 64 \times 1099


= 70336


So, sum of all 3 digits number divisible by 7=70336

❤Hope it helps uh ❤

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@Laughterqueen

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