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Find the sum of all the three digit natural number which are multiples of 7

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3 digit natural NUMBER which are multiple of 7 are 105,112,119.......994
First TERM a=105
Common difference d=7
an=a+(n-1)d
994=105+(n-1)7
994-105=7n-7
884+7=7n
n=128
sum of the term
n/2*(a+l)#
128/2*(105+994)
64*1099
=70336
therefore the answer is 70336


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