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Find the sum of first 51 terms of an A.Pwhosesecond & third terms areare 14 & 18 respectively |
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Answer» 5610Step-by-step explanation:a 2 =14 and a 3 =18Common difference, d=a 3 −a 2 =18−14=4Now a 2 =a+d=14a+4=14a=10Now, sum of 51 termsS N = 2N (2a+(n−1)d)S 51 = 251 (2(10)+(51−1)4)= 251 (20+200)= 251×220 =51×110=5610S 51 =5610 |
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