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Find the sum of series 1^2+3^2+5^2+…………………………..+11^2.(a) 279(b) 286(c) 309(d) 409The question was asked in final exam.This intriguing question comes from Sum to n Terms of Special Series in division Sequences and Series of Mathematics – Class 11 |
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Answer» RIGHT choice is (b) 286 Explanation: 1^2+3^2+5^2+…………………………..+11^2 = (1^2+2^2+3^2+……+11^2) – (2^2+4^2+6^2+8^2+10^2) = (1^2+2^2+3^2+……11^2) – 2^2(1^2+2^2+3^2+4^2+5^2) = 11*12*23/6 – 4*5*6*11/6 = 506 – 220 = 286. |
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