1.

Find the sum of the first 40 denominators divisible by 6.​

Answer»

-step explanation:We KNOW that the first 40 positive integers DIVISIBLE by 6 are 6,12,18,....This is an AP with a = 6 and d = 6.S40= 20[2(6) +(40-1)6] =20[12+234] =4920.



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