Find the sum of the first 40 positive integers divisible by 6. – InterviewSolution

1.

Find the sum of the first 40 positive integers divisible by 6.

Answer»

Answer:-

NUMBERS divisible by 6 are 6,12,18,24.......

so, a=6,d=6,n=40

wkt,, sn=n/22a+(n-1*)d

sn=40/2*2(6)+(40-1)6

sn=20*12+39(6)

sn=20(12+234)

sn=20(246)

sn=4920..

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