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Find the sum of the kinetic and the potential energies of an electron in the first Bohr orbit. Explain the meaning of the sign of the total energy |
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Answer» Solution :`E= K+U= (mv^(2))/(2)- (e^(2))/(4piepsilon_(0)(a_(0)))= -13.6eV` The minus sign MEANS that the formation of a hydrogen ATOM from a free proton and an electron is accompanied by the LIBERATION of energy equal to 13.6 eV. |
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