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Find the sum of the products of the corresponding terms of the sequences 2,4, 8, 16, 32 and 128, 32, 8, 2, `1/2`. |
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Answer» let the first sequence is `a_n` let the second sequence as `b_n` we have to find `C_n = a_nb_n` `= 256(2*1/4)^(n-1)` `sum C_n = s_5= (256(1-(1/2)^5))/(1- 1/2)` `= (256(1-1/32))/(1/2)` `=(2*256*31)/32` `= 16*31 = 496` answer |
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