1.

Find the sum of the products of the corresponding terms of the sequences 2,4, 8, 16, 32 and 128, 32, 8, 2, `1/2`.

Answer» let the first sequence is `a_n`
let the second sequence as `b_n`
we have to find `C_n = a_nb_n`
`= 256(2*1/4)^(n-1)`
`sum C_n = s_5= (256(1-(1/2)^5))/(1- 1/2)`
`= (256(1-1/32))/(1/2)`
`=(2*256*31)/32`
`= 16*31 = 496`
answer


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