1.

Find the sum of the series 1+3.5+6+8.5+...+101.--+- 629,2349xTIF 1913 – 17​

Answer»

Answer:

Hi everyone hru guy's

Step-by-step explanation:

SN = (n/2)(a1 + an)

a1 = 1

But we NEED first to determine n.

To do that we need d:

d = 3.5-1 = 6-3.5 = 8.5-6 = 2.5

an = a1 + (n - 1)∙d

101 = a1 + (n - 1)∙2.5

Solve that and get n = 41

Sn = (n/2)(a1 + an)

S41 = (41/2)(1 + a41)

S41 = (41/2)(1 + 101)

S41 = (41/2)(102)

S41 = 2091

I HOPE U like my answer and please follow me❤❤❤


Discussion

No Comment Found

Related InterviewSolutions