Find the sum of the series 11^3+12^3+13^3+...28^3 – InterviewSolution

1.	Find the sum of the series 11^3+12^3+13^3+...28^3
Answer» 112 + 122 + 132 + ... + 202) = (12 + 22 + 32 + ... + 202) - (12 + 22 + 32 + ... + 102) Ref: (12 + 22 + 32 + ... + n2) = 1 n(n + 1)(2n + 1) 6= 20 x 21 x 41 - 10 x 11 x 21 6 6= (2870 - 385)= 2485.

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