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Find the sum `Sigma_(r=1)^(oo) (r-2)/((r+2)(r+3)(r+4))` |
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Answer» Correct Answer - `1/12` `T_(r)=(r-2)/((r+2)(r+3)(r+4))=(r(r+4)-(r+1)(r+2))/((r+2)(r+3)(r+4))` `=r/((r+2)(r+3))-((r+1))/((r+3)(r+4))` `therefore S_(n)=sum_(r=1)^(n)T_(r)=1/12-((n+1))/((n+3)(n+4))` `thereforeS_(oo)=1/12` |
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