InterviewSolution
Saved Bookmarks
| 1. |
Find the sum to indicated number of terms in each of the geometric progressions : 0.15, 0.015, 0.0015, . . . , 20 terms. |
|
Answer» In the given GP, First-term, `a = 0.15` Common ratio, `r = 0.1` So, Sum of first 20 terms, `S_20 = (a(1-r^20))/(1-r)` `S_20 = (0.15(1-(0.1)^20))/(1-0.1) = 0.15/0.9(1-(0.1)^20)` `S_20 = 1/6(1-(0.1)^20)` |
|