1.

Find the tenth term AP (√8,√18, √32)​

Answer»

Answer

The 10TH TERM of the given AP is 10√2 or √200

\bf \large \underline{Given : }

The AP is

  • √8 , √18 , √32

\bf \large \underline{To \: Find : }

  • The 10th term of the AP

\bf \large \underline{Solution : }

Given , the AP is

➝ √8 , √18 , √32

➝ 2√2 , 3√2 , 4√2

Therefore ,

FIRST term , a = 2√2

and COMMON difference,

» d = 3√2 - 2√2

» d = √2

We know that ,

\longrightarrow \: \: \rm a _{n} = a + (n - 1)d \\ \\ \implies \rm a_{10} = 2 \sqrt{2} + (10 - 1) \sqrt{2} \\ \\ \rm \implies a_{10} = 2\sqrt{2} + 9 \sqrt{2} \\ \\ \rm\implies a_{10} = 10 \sqrt{2}

Therefore, the 10th term of the AP is 10√2 or √200


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