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Find the tion of the line passing through the point `(-2,-4)`and perpendicular to the line `3x-y+5=0` |
Answer» We have lt`3x-y+5=0 Rightarrow y=3x+5` `therefore` slope of the given line=3 `[therefore y=mx+c]` and slope of the line perpendicular to the given line`=-(1)/(3) " "[therefore m_(2)=-(1)/(m_(1))]` Now, the equation of a line with slope `-(1)/(3)` and passing through the point (-2,-4) is given by `(y-(-4))/(x-(-2))=-(1)/(3) Rightarrow (y+4)/(x+2)=(-1)/(3)" "[therefore ((y-y_(1)))/((x-x_(1)))=m]` `Rightarrow 3(y+4)=-(x+2)` `Rightarrow x+3y=14=0`, which is the required equation. |
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