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Find the torque of a force `F=(hat(i)2 +hat(j)-3hat(k))N` about a point O. The position vector of point of application of force about O is `r = (2 hat(i) + 3 hat(j) - hat(k))m`. |
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Answer» Torque, `tau=rxxF=|{:(hat(i),hat(j),hat(k)),(2,3,-1),(1,2,-3):}|` `tau=hat(i) (-9+2)+hat(j)(-1+6)+hat(k)(4-3)` or `tau=(-7hat(i)+5 hat(j)+hat(k))"Nm"`. |
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