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Find the total charge stored in the network of capacitors connected between A and B as shown in figure. |
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Answer» SOLUTION :The GIVEN network can be redrawn as shown here . The equivalent capacitance of the network is given as : `1/C=(1)/((C_1+C_2))+(1)/((C_3+C_4))` `=1/((4+6)MUF)+1/((2+3)muF)=(1/10+1/5)=3/10 muF` `IMPLIES C = 10/3muF` `:.` Total CHARGE on the network `Q=CV=(10/3muF)xx3V=10muC`
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