1.

Find the total no. of alkynes that on catalytic reduction gives 3-ethyl-4 methylheptane.

Answer»


SOLUTION :`CH_(3)-CH_(2)-CH_(2)-underset(CH_(3))underset(|)CH-underset(CH_(2)-CH_(3))underset(|)CH-CH_(2)-CH_(3)`
(ii) `CH=C-CH_(2) -underset(CH_(3))underset(|)CH-underset(CH_(2)CH_(3))underset(|)CH-CH-CH_(2)CH_(3)`
(iii) `CH_(3)-C=C-underset(CH_(3))underset(|)C-underset(CH_(2)CH_(3))underset(|)CH-CH_(2)CH_(3)`
Alkynes (i), (ii) and (iii)
PRODUCES 3-ethyl-4-methyl HEPTANE on catalytic reduction.


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