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Find the total number of stereoisomer for each compound : |
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Answer» (2) `2^(2)=4` (3) `2^(n-1)+2^((n//2-1))+2^(2//1)+2^((2//2-1)=2^(1)+2^(@)=2^(1)+1=3` (4) 4 (5) `2^(3)rArr8`
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