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Find the turns in an solenoid of inductance 23.4mH , current 2A and area 15cm.(a) 900(b) 400(c) 498(d) 658The question was posed to me in an interview for job.My query is from Magnostatic Energy in section Magnetostics of Electromagnetic Theory

Answer»

The correct choice is (c) 498

The BEST I can explain: The inductance of any MATERIAL(coil) is given by L = μ N^2A/I.

Put L = 23.4 x 10^-3, I = 2 and A = 0.15, we get N as 498 turns.



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