1.

Find the value of: (1)(20+3−1)×32 (ii)(2−1×3−1)÷2−3 (iii)(12)−2+(13)−2+(14)−2

Answer»

Find the value of:

(1)(20+3−1)×32

(ii)(2−1×3−1)÷2−3

(iii)(12)−2+(13)−2+(14)−2



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