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Find the value of (2^0+3^0+4^0)-(4^0-3^0-2^0) |
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Answer» Step-by-step explanation: those values whose POWER is zero the ANSWER of that value is ALWAYS 1. Now (2^0+3^0+4^0)-(4^0-3^0-2^0) (1+1+1)-(1-1-1) (3)-(-2) 3+2 5 |
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