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Find the value of 2x²+ 5x² +7x² -x +41,when x =-2 -root 3 i |
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Answer» The answer is 214.564Step-by-step EXPLANATION:GIVEN 2x²+5x²+7x²-x+41if x= -2√3substitute 'x'value in the equation 2(-2√3)²+5(-2√3)²+7(-2√3)²-(-2√3)+412(4X3)+5(4x3)+7(4x3)+2√3+412x12+5x12+7x12+2√+4126+60+84+2√3+41the value of √3=1.732211+2x1.732211+3.564214.564 |
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