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Find the value of'a' and 'b' so that polynomial x³-ax²-13 is exactly divisible by (x-1)as well as (X+3) |
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Answer» Answer: Let p(X) = X3 – AX2 – 13x + b If (x – 1) and (x + 3) are factors of p (x), then remainders p (1) = 0 and p (-3) 0 p(1) = 13 – a x 12 – 13 x 1 + b = 0 => 1 – a – 13 + b = 0 |
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