Find the value of'a' and 'b' so that polynomial x³-ax²-13 is exactly divisible by (x-1)as well as (X+3)

Find the value of'a' and 'b' so that polynomial x³-ax²-13 is exactly

1.	Find the value of'a' and 'b' so that polynomial x³-ax²-13 is exactly divisible by (x-1)as well as (X+3)
Answer» <html><body><p><strong>Answer:</strong></p><p>Let p(<a href="https://interviewquestions.tuteehub.com/tag/x-746616" style="font-weight:bold;" target="_blank" title="Click to know more about X">X</a>) = <a href="https://interviewquestions.tuteehub.com/tag/x3-1463140" style="font-weight:bold;" target="_blank" title="Click to know more about X3">X3</a> – <a href="https://interviewquestions.tuteehub.com/tag/ax2-889799" style="font-weight:bold;" target="_blank" title="Click to know more about AX2">AX2</a> – 13x + b If (x – 1) and (x + 3) are factors of p (x), then remainders p (1) = <a href="https://interviewquestions.tuteehub.com/tag/0-251616" style="font-weight:bold;" target="_blank" title="Click to know more about 0">0</a> and p (-3) 0 p(1) = <a href="https://interviewquestions.tuteehub.com/tag/13-271882" style="font-weight:bold;" target="_blank" title="Click to know more about 13">13</a> – a x 12 – 13 x 1 + b = 0 => 1 – a – 13 + b = 0</p></body></html>