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Find the value of `a`if `[a-b2a+c2a-b3c+d]=[-1 5 0 13]` |
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Answer» Correct Answer - `a=1, b=2, c=3, d=4` `[(a-b,2a+c),(2a-b,3c+d)]=[(-1,5),(0,13)]` As the two matrices are equal, their corresponding elements are also equal. Comparing the corresponding elements, we get `a-b=-1` (1) `2a-b=0` (2) `2a+c=5` (3) `3c+d=13` (4) From (2), we have `b=2a` Then, from (1), we have `a-2a=-1` or `a=1` `implies b=2` Now, from (3), we have `2xx1+c=5` or `c=3` From (4), we have `3xx3+d=13` or `9+d=13` or `d=4` `:. a=1, b=2, c=3` and `d=4` |
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