Find the value of a3 + b3 +c3 – 3abc, when a + b + c = 8 and a b + b c + c a = 25.

Find the value of a3 + b3 +c3 – 3abc, when a + b + c = 8 and a b + b

1.	Find the value of a3 + b3 +c3 – 3abc, when a + b + c = 8 and a b + b c + c a = 25.
Answer» <html><body><p><strong>Step-by-step explanation:</strong></p><p><a href="https://interviewquestions.tuteehub.com/tag/first-461760" style="font-weight:bold;" target="_blank" title="Click to know more about FIRST">FIRST</a> we find the <a href="https://interviewquestions.tuteehub.com/tag/value-1442530" style="font-weight:bold;" target="_blank" title="Click to know more about VALUE">VALUE</a> of a </p><p><a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a></p><p> +b </p><p>2</p><p> +<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a> </p><p>2</p><p> </p><p>a </p><p>2</p><p> +b </p><p>2</p><p> +c </p><p>2</p><p> =(a+b+c) </p><p>2</p><p> −2(ab+bc+ca)=<a href="https://interviewquestions.tuteehub.com/tag/8-336412" style="font-weight:bold;" target="_blank" title="Click to know more about 8">8</a> </p><p>2</p><p> −2×19=64−38=26</p><p>∴a </p><p>3</p><p> +b </p><p>3</p><p> +c </p><p>3</p><p> −3abc=(a+b+c)(a </p><p>2</p><p> +b </p><p>2</p><p> +c </p><p>2</p><p> −ab−bc−ca)=(8)(26−19)=8×7=56</p></body></html>