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Find the value of current( rms and peak) through a capacitor of 10 mu Fwhen connected to a source of 110 V at 50 cycles supply. What is its capacitive reactance? |
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Answer» Solution :Data supplied `C= 10 mu F = 10 xx 10^(-6) F, E_(rms) = 110 V , v = 50 Hz` ` X_C = (1)/(omega C)= (1)/(2pi v C) = (1)/(2 xx 3.14 xx 50 xx 10^(-5)) = 318.5 Omega` ` I_(rms) = (E_(rms) )/(X_C) = (110)/(318.5) = 0.345 A` |
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