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Find the value of emf induced in the rod for the following cases. The figures are self explanatory. |
Answer» Solution : Figure SHOWS a closed coil ABCA moving in a uniform magnetic field B with a velocity v. The flux passing through the coil is a constant and therefore the induced emf is zero. Now consider ROD AB, which is a part of the coil. Emf induced in the rod = B L v. Now SUPPOSE the emf induced in part ACB is E, as shown in figure. Since the emf in the coil is zero, Emf (in ACB) + Emf (in BA) = 0 `-E+vBL=0` E=vBL Thus emf induced in any path joining A and B is same, provided the magnetic field is uniform. ALSO the equivalent emf between A and B is BLv (here the TWO emf’s are in parallel) |
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