InterviewSolution
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InterviewSolution
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Find the value of: i) `sin^(-1)(sinpi/3)` ii) `cos^(-1)(cos(2pi)/3))`, iii) `tan^(-1)(tanpi/4)` |
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Answer» We have, i) `sin^(-1)(sinpi/3)=pi/3`, since `pi/3 in [-pi/2, pi/2]`. ii) `cos^(-1)(cos(2pi)/3)=(2pi)/3`, Since `(2pi)/3 in [0,pi]` iii) `tan^(-1)(tanpi/4)=pi/4`, since `pi/4 in (-pi/2,pi/2)` |
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