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Find the value of i³⁵ |
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Answer» i⁻³⁵ =i⁻³⁴⁻¹ =(i²)⁻¹⁷×(i⁻¹) =(-1)⁻¹⁷(1/i) =1/(-1)¹⁷(1/i) =(-1)(1/i) =-1/i =0+i(-1/i²) =0+i(-1/-1) =0+i.1 where a=0, b=1 Step-by-step EXPLANATION: |
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