1.

Find the value of k if 5 is a zero of polynomial. P(y) =4y²-16y²+ky-5

Answer»

-step explanation:Given that 5 is the ZERO of the polynomial p(y).THEREFORE,p(y)=-12y²+ky-5 =>p(-5)=-12(-5)²+k(-5)-5 =295-5k



Discussion

No Comment Found