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Find the value of k if 5 is a zero of polynomial. P(y) =4y²-16y²+ky-5 |
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Answer» -step explanation:Given that 5 is the ZERO of the polynomial p(y).THEREFORE,p(y)=-12y²+ky-5 =>p(-5)=-12(-5)²+k(-5)-5 =295-5k |
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