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Find the value of n if: (i) (n+2)! = 12. n! (ii) (n+2)! = 60-. (n-1)! =({2.4.6....(2n)}{1.3.5....(2.-1)})/(n!) = (2^(n){1.2.3...n}{1.3.5.......(2n-1)})/(n!) = 2^(n) {1.3.5....(2n-1)} = R.H.S. Hence Proved. (iii) (n+3)! = 2550 (n+1)! (iv) (n-2)! = 132. (n-4)!. |
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