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Find the value of p for the following distribution whose mean is 16.6x:81215p202530y:121620241684 |
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Answer»
Given, Mean = 16.6 \(\frac{\sum yx}{N}=16.6\) \(\frac{24p+1228}{100}=16.6\) 24p + 1228 = 1660 24p = 1660 – 1228 24p = 432 p = \(\frac{432}{24}=18\) |
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