1.

Find the value of p for the following distribution whose mean is 16.6x:81215p202530y:121620241684

Answer»
Xyyx
81296
1216192
1520300
p2424p
2016320
258200
304120
N = 100\(\sum\)yx = 24p + 1228

Given,

Mean = 16.6

\(\frac{\sum yx}{N}=16.6\)

\(\frac{24p+1228}{100}=16.6\)

24p + 1228 = 1660

24p = 1660 – 1228

24p = 432

p = \(\frac{432}{24}=18\)



Discussion

No Comment Found

Related InterviewSolutions