Find the value of p for which the points (-5,1) , (1,p) and (4,-2) are

1.	Find the value of p for which the points (-5,1) , (1,p) and (4,-2) are collinear
Answer» EXPLANATION. point are = (-5,1),(1,p),(4,-2) are collinear TO FIND VALUE OF P. Conditions of collinear x1 ( y2 - y3) + X2 ( y3 - y1) + x3 ( y1 - y2) = 0 x1 = -5 x2 = 1 x3 = 4 y1 = 1 y2 = p y3 = -2 -5[p - (-2) ] + 1 [ -2 - 1 ] + 4 [ 1 - p ] = 0 -5 [ p + 2] + 1 [ -3] + 4 - 4p = 0 -5p - 10 - 3 + 4 - 4p = 0 -9P - 9 = 0 -9p = 9 p = -1 Therefore value of p = -1

Find the value of p for which the points (-5,1) , (1,p) and (4,-2) are collinear

Answer»

EXPLANATION.

point are = (-5,1),(1,p),(4,-2) are collinear

TO FIND VALUE OF P.

Conditions of collinear

x1 ( y2 - y3) + X2 ( y3 - y1) + x3 ( y1 - y2) = 0

x1 = -5

x2 = 1

x3 = 4

y1 = 1

y2 = p

y3 = -2

-5[p - (-2) ] + 1 [ -2 - 1 ] + 4 [ 1 - p ] = 0

-5 [ p + 2] + 1 [ -3] + 4 - 4p = 0

-5p - 10 - 3 + 4 - 4p = 0

-9P - 9 = 0

-9p = 9

p = -1

Therefore value of p = -1

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Find the value of p for which the points (-5,1) , (1,p) and (4,-2) are collinear​